2[2(x+y)-6(3x-2y)]=

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Solution for 2[2(x+y)-6(3x-2y)]= equation:


Simplifying
2[2(x + y) + -6(3x + -2y)] = 0
2[(x * 2 + y * 2) + -6(3x + -2y)] = 0
2[(2x + 2y) + -6(3x + -2y)] = 0
2[2x + 2y + (3x * -6 + -2y * -6)] = 0
2[2x + 2y + (-18x + 12y)] = 0

Reorder the terms:
2[2x + -18x + 2y + 12y] = 0

Combine like terms: 2x + -18x = -16x
2[-16x + 2y + 12y] = 0

Combine like terms: 2y + 12y = 14y
2[-16x + 14y] = 0
[-16x * 2 + 14y * 2] = 0
[-32x + 28y] = 0

Solving
-32x + 28y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-28y' to each side of the equation.
-32x + 28y + -28y = 0 + -28y

Combine like terms: 28y + -28y = 0
-32x + 0 = 0 + -28y
-32x = 0 + -28y
Remove the zero:
-32x = -28y

Divide each side by '-32'.
x = 0.875y

Simplifying
x = 0.875y

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